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Sunday, January 19, 2020

QUANTITY SURVEY & RATE ANALYSIS






Calculate the quantity of cement, sand & aggregate in concrete And Also Calculate Quantity of Rate.




                            For example,
We take,
Ratio of M-15 (1:2:4)
Total volume considered = 1 m^3
Sum of ratio = 1+2+4 = 7
Dry volume = 1 x 1.54 = 1.54 m^3  (always take)
We know that,
Density of cement = 1440 kg/m^3
Density of sand = 1450 kg/m^3
Density of aggregate = 1500 g/m^3

For Cement,
    In cum = (dry volume x cement/sum of ratio)
                 = 1.54 x 1/7 = 0.22 m^3
    In kg = (dry volume x cement x density of cement/ sum of ratio)
                          =    1.54 x 1 1440 / 7 = 316.8 kg

   In beg,
                       We know that.
   1 beg of cement = 50 kg

  > No of begs  = In kg / 1 beg cement

                                     = 316.8 kg/50kg  = 6.336 begs, appr. = 7Nos
Ø  In cubic feet (cft)
Volume of 1 beg cement = 1.226 cft


= No of begs x vol of 1 beg cement = 6.336 x 1.226 = 7.76 cft


For Sand,

Ø In cum = 1.54 x2/ 7 = 0.44 m^3

Ø  In kg = 1.54x2x1450/7 = 638 kg, (where 1450 is sand density)

In cft = 0.44 x35.3147
          = 15.54   cft          
(Note, 1 m^3 = 35.3147 ft^3)

For aggregate,

Ø  In m^3 = 1.54 x 4 /7 = 0.88 m^3

In kg = 0.88 x 1500 = 1320 kg, (where 1500 is aggregate density)

Ø  In cft = 0.88 x 35.3147, (1 m^3 = 35.3147 ft^3)
           = 31.07 cft 


RATE ANALYSIS M-15 FOR 1 M^3

S.NO
Items
Quantity
Rate
Amount (Q XR)
1
Cement
beg
250/beg
1750
2
Sand
15.54 cft
17/cuft
265
3
Aggregate
31.07 cft
22/cft
684
4
Bhisti
0.2day/m^3
200/day
40
5
Mason
0.37day/m^3
350/day
130
6
Labour
3.5day/m^3
200/day
700



Total
3569 Rs

                                 Add 1.5 % for equipment =    3569 x 1.5/100 = 53 Rs
                                                                       Total = 3569 +53 = 3622 Rs

Add 10 % of contractor    = 3622 x10/100
                                             =      362 Rs
Total = 3622 + 362 = 3984 Rs

Note, the above calculation is found out only for 1 m^3,

It you want to calculate M-15m^3 than always remember, Bhisti, Mason & 

Labour in multiply in 15, for as (Mason, 0.37day/m^3 Rate, 350/day, Bhisti,

 0.2day/m^3 Rate, 200/day & Labour, 3.5day/m^3 Rate, 200/day the volume taken IS code)
                         EX.         = 0.37 x15 x 350.
So that. Now you can calculate for any rate analysis M-20, M-10 etc.,

Case 1


Ø For materials cost =   1750+265+684 =2699 Rs

                            (Where, materials cost is sum of cement, sand & aggregate amount that is given above table)

Ø Add 10% contractor profit = 2699 x 10 /100 = 269.9 Rs
                                                 Total sum = 2699+269.9 = 2969 Rs


Case 2

Ø                                     For labour cost = 40+130+700 = 870 Rs

Add 10% contractor profit = 870x10/100 = 87 Rs
                                        Total =  870+87 = 957 Rs

Case 3  
          
Ø For equipment = 53 Rs
                               Add 10% contractor profit = 53x10/100  = 5.3 Rs
                                           Total = 53+5.3 =58 Rs           









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